Thursday, April 13, 2017

Geometry Problem 1332: Two Squares Side by Side, Triangle, Area

Geometry Problem. Post your solution in the comment box below.
Level: Mathematics Education, High School, Honors Geometry, College.

Details: Click on the figure below.

Geometry Problem 1332: Two Squares Side by Side, Triangle, Area.

5 comments:

  1. Extend BC and GF at P. S=S(ABPG)-1/2 S(ABPG)-1/2 S(DEFG)-S(CPFE)-S(BCE)
    S= 36

    ReplyDelete
    Replies
    1. How did you calculate S(BCE)?
      you have nothing to calculate.

      Delete
    2. name AD = a
      S = [(a+6)∙a] - [1/2(a+6)∙a] - [1/2(6∙6)] - [(a-6)∙6] - [1/2(a-6)∙a]

      Delete
  2. https://goo.gl/photos/ZgtosScujk4knoyr9

    Draw rectangle BDHK as shown on the sketch
    Area(BGE)= ½. EG*BK= ½. DH*EG= area(EDG)
    = ½. 6*6= 18

    ReplyDelete
  3. Problem 1332
    Is BD//EG then (EBG)=(EDG)=DE.DG/2=6.6/2=18.

    ReplyDelete